-x^2+36=2x+13

Solution for -x^2+36=2x+13 equation:

-x^2+36=2x+13

We move all terms to the left:

-x^2+36-(2x+13)=0

We add all the numbers together, and all the variables

-1x^2-(2x+13)+36=0

We get rid of parentheses

-1x^2-2x-13+36=0

We add all the numbers together, and all the variables

-1x^2-2x+23=0

a = -1; b = -2; c = +23;
Δ = b2-4ac
Δ = -22-4·(-1)·23
Δ = 96
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{96}=\sqrt{16*6}=\sqrt{16}*\sqrt{6}=4\sqrt{6}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-4\sqrt{6}}{2*-1}=\frac{2-4\sqrt{6}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+4\sqrt{6}}{2*-1}=\frac{2+4\sqrt{6}}{-2}
$